Page 5 of 5

PostPosted: Fri Jan 06, 2017 5:02 pm
by CuddlyCaucasian
1 3 7 6 50 100

Target Number: 709


You have (expired on 2017-01-06 18:12:47).

PostPosted: Fri Jan 06, 2017 5:12 pm
by CuddlyCaucasian
Both players came up with the correct response, this one sure was a doozy, huh?
(100*7)+6+3=709

The score is now 38-36, meaning the Conundrum will determine the winner. It will be posted in (expired on 2017-01-06 18:13:58), so be ready

PostPosted: Fri Jan 06, 2017 5:14 pm
by CuddlyCaucasian
U I C Y R T C R I

PostPosted: Fri Jan 06, 2017 5:15 pm
by Haschel Cedricson
Circuitry?

PostPosted: Fri Jan 06, 2017 5:15 pm
by zoraster
uh huh

PostPosted: Fri Jan 06, 2017 5:16 pm
by CuddlyCaucasian
Yep, Haschel wins the 10 points, and the Brawl!

I apologize again for the scoring rules with the numbers round. In hindsight, I would have changed it from the original rules to make it so whoever is closest gets 5 points regardless. I hope you both enjoyed the game despite that flaw in the rules.

PostPosted: Fri Jan 06, 2017 5:17 pm
by Haschel Cedricson
Nicely fought, zor; my heart has been racing ever since you said "CLAMOR".

PostPosted: Fri Jan 06, 2017 5:18 pm
by zoraster
right.

PostPosted: Sun Jan 08, 2017 3:14 am
by Mitillos
Sorry to butt in, but I only caught up to this game now.

852 = ((5 * 10 - 10) * 7 + 4) * 3

Given a specific target number, there is always a two in three chance or higher (generally significantly higher) that the six numbers you get can hit that number precisely. Getting within 10 of the target is virtually guaranteed, unless you hit a terrible set, like {1, 1, 2, 2, 3, 3}.

PostPosted: Sun Jan 08, 2017 5:19 am
by Cheery Dog
Damn you Mitillos, I thought I was going to be good to post a 843 as proof it could be within 10

PostPosted: Sun Jan 08, 2017 5:24 am
by Mitillos
(10 * 10 + 5 * 4) * 7 + 3?

PostPosted: Sun Jan 08, 2017 5:40 am
by Cheery Dog
Yeah.

I did stop looking after seeing that though.

PostPosted: Sun Jan 08, 2017 6:06 am
by Mitillos
You can also get within 5 without hitting the target, with (4 * 3 * 10 + 10 / 5) * 7 = 854.

PostPosted: Sun Jan 08, 2017 9:01 am
by D3f3nd3r
Damn multiples of 7

PostPosted: Sun Jan 08, 2017 9:22 am
by zoraster
cheers!

PostPosted: Sun Jan 08, 2017 10:50 am
by DeathRowKitty
If you happen to know the factors of 85, I think the most obvious way to get close is (10 + 7) * 5 * 10 + 3 or (10 + 7) * 5 * 10 + 4 - 3, both of which get you within 1.