Math and Logic Puzzles

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Post Post #160 (isolation #0) » Sun Jul 10, 2011 3:54 pm

Post by cjdrum »

Oh! Gotta add this to my egosearch.

Aaaand...
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Post Post #161 (isolation #1) » Sun Jul 10, 2011 3:55 pm

Post by cjdrum »

Done!
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Post Post #164 (isolation #2) » Sun Jul 10, 2011 6:19 pm

Post by cjdrum »

Hmm...

Spoiler:
4 x 3 x 2 x 1
x
2 x 1
x
2 x 1
x
2 x 1
x
2 x 1
x
2 x 1
x
2 x 1
?

RED
is the number of permutations for the first row.
ORANGE
is the number of permutations for the first two boxes of the second row
YELLOW
is the number of permutations for the third and fourth boxes of the second row
GREEN
is the number of permutations for the first box of rows three and four
BLUE
is the number of permutations for the second box of rows three and four
INDIGO
is the number of permutations for the third and fourth boxes of row three
VIOLET
is the number of permutations for the third and fourth boxes of row four

|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|
|---|


That equals... 1536. WHAT JUST HAPPENED?

1536 / 288 = 16/3

I can't have accidentally multiplied by five-and-a-bit, can I?


PI?
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Post Post #168 (isolation #3) » Sun Jul 10, 2011 8:26 pm

Post by cjdrum »

12.5 units?
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Post Post #179 (isolation #4) » Mon Jul 11, 2011 11:42 am

Post by cjdrum »

Xdaamno wrote:About the folding paper: what's the question? Is it how many units do you need to fold the bottom right corner
so that
it's above the bottom left? Anything between 5 units and sqrt(125) units can get you there, right?

FT?
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Post Post #192 (isolation #5) » Tue Jul 12, 2011 7:35 am

Post by cjdrum »

Is it just:

5 sqrt(5)
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Post Post #304 (isolation #6) » Sun Jul 17, 2011 11:26 am

Post by cjdrum »

One, if the wives and sacks and cats and kittens aren't going too.

Or if they're already there.
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Post Post #314 (isolation #7) » Mon Jul 18, 2011 3:24 pm

Post by cjdrum »

Sorry, been trying to think of one.

Okay.
I have 8 gumballs in a bag. I also have 8 friends, who each want a gumball (and I don't want any). I give one gumball to each friend, and when I am done there is one gumball left in the bag. How is this possible?
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Post Post #316 (isolation #8) » Mon Jul 18, 2011 3:35 pm

Post by cjdrum »

No, one of my friends did not die.
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Post Post #318 (isolation #9) » Mon Jul 18, 2011 3:43 pm

Post by cjdrum »

. . .

Yes.
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Post Post #320 (isolation #10) » Mon Jul 18, 2011 4:10 pm

Post by cjdrum »

It's.. kinda.. Logic...

I just couldn't think of anything else.
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Post Post #380 (isolation #11) » Tue Jul 19, 2011 10:22 am

Post by cjdrum »

Lime
Lie
?
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Post Post #481 (isolation #12) » Thu Jul 21, 2011 1:34 pm

Post by cjdrum »

Tazaro wrote:Here is a riddle:
What royal person can be constructed from printer cable?

I'm guessing you shuffle the letters...

P R I N
T
E R
C
A
B
L
E


P R I N
C
E
A
L
B
E R
T


Is the answer Prince Albert?
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Post Post #482 (isolation #13) » Thu Jul 21, 2011 1:35 pm

Post by cjdrum »

Dammit, ninja'd by the hint.
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Post Post #484 (isolation #14) » Thu Jul 21, 2011 1:40 pm

Post by cjdrum »

Cool.

Puzzle up in a few minutes.
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Post Post #485 (isolation #15) » Thu Jul 21, 2011 1:45 pm

Post by cjdrum »

A cylindrical object, with length 15cm and radius 4cm, is placed between two parallel bars, which are exactly 12cm apart.

The cylinder is turned so that it touches (but does not lie on) the bars.

What is the angle between each bar and the length of the cylinder, to the nearest minute?
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Post Post #490 (isolation #16) » Fri Jul 22, 2011 10:54 am

Post by cjdrum »

That's exactly the answer I got, so... Go, Tazaro!
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Post Post #495 (isolation #17) » Fri Jul 22, 2011 3:15 pm

Post by cjdrum »

Do we know that they are integers?
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Post Post #523 (isolation #18) » Sat Jul 23, 2011 4:01 pm

Post by cjdrum »

Is Samwise able to dig anywhere other than directly on the perimeter?
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Post Post #536 (isolation #19) » Mon Jul 25, 2011 7:20 pm

Post by cjdrum »

Spoiler: Value of n, and their workings
  1. 1
  2. 0.5 + 0.5
  3. 0.5 + 0.25 + 0.25
  4. 0.25 + 0.25 + 0.25 + 0.25
  5. 0.5 + 0.25 + 0.1 + 0.1 + 0.05
  6. 0.25 + 0.25 + 0.25 + 0.1 + 0.1 + 0.05
  7. 0.25 + 0.25 + 0.25 + 0.1 + 0.05 + 0.05 + 0.05
  8. 0.25 + 0.25 + 0.25 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  9. 0.25 + 0.25 + 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05
  10. 0.25 + 0.25 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  11. 0.25 + 0.25 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  12. 0.25 + 0.25 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  13. 0.25 + 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  14. 0.25 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  15. 0.25 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  16. 0.25 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  17. 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  18. 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  19. 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  20. 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05
  21. 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  22. 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  23. 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  24. 0.1 + 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  25. 0.1 + 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  26. 0.1 + 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  27. 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  28. 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.25 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  29. 0.1 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.1 + 0.1 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  30. 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.1 + 0.1 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  31. 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.1 + 0.05 + 0.05 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01
  32. 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.05 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01 + 0.01


I'll keep working on it in a bit.
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Post Post #539 (isolation #20) » Mon Jul 25, 2011 8:28 pm

Post by cjdrum »

Kcdaspot wrote:
killerjester wrote:You are given n coins of denominations 1, 0.5, 0.25, 0.1, 0.05 and 0.01 (6n coins altogether). You are then asked to choose n out of these 6n coins that sum up to exactly 1. What is the smallest n for which this is
impossible
?

1.

See
my
bold.

ChaosOmega wrote:n=77

I think this is right.

Espeonage wrote:3.

.5 + .25 + .1 + 3x .5

What?
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Post Post #555 (isolation #21) » Tue Jul 26, 2011 4:03 pm

Post by cjdrum »

The deaded person was born last week or slightly less recent, after any holidays had occured?
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Post Post #556 (isolation #22) » Tue Jul 26, 2011 4:04 pm

Post by cjdrum »

So... Birth -> no holidays -> Death
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Post Post #559 (isolation #23) » Tue Jul 26, 2011 4:17 pm

Post by cjdrum »

Answer to kiwi's rhetorical question: Because he just walked in to what was meant to be a meeting with old friends/family, and found her dead.

:P
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Post Post #580 (isolation #24) » Tue Jul 26, 2011 8:10 pm

Post by cjdrum »

Code: Select all

 4 | 9 | 2
-----------
 3 | 5 | 7
-----------
 8 | 1 | 6 
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Post Post #584 (isolation #25) » Wed Jul 27, 2011 1:12 pm

Post by cjdrum »

Argh. Always hard to think of one.

Someone else go.
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Post Post #600 (isolation #26) » Wed Jul 27, 2011 2:30 pm

Post by cjdrum »

You have to split it at the same time so that when, after 20 hours, people die, you can work out a common wine that each person had.

Sadly, I can't do the maths for that at the moment.
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Post Post #608 (isolation #27) » Wed Jul 27, 2011 2:50 pm

Post by cjdrum »

99. Edit coming.
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Post Post #610 (isolation #28) » Wed Jul 27, 2011 2:54 pm

Post by cjdrum »

Spoiler: My solution
The wise men devise a code before the king lines them up.

The first man will count up all the red hats in front of him. If it is odd, he will say "red", and if it is even he will say "blue". He has a 50/50 chance of survival.
The second man again counts all the red hats in front of him. If the first man said "red" and there is an odd number of red hats, his hat is blue. If the first man said "red" and there is an even number of red hats, his hat is red. If the first man said "blue" and there is an odd number of red hats, his hat is red. If the first man said "blue" and there is an even number of red hats, his hat is blue.

This continues down the line until the last 99 people are saved.
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Post Post #613 (isolation #29) » Wed Jul 27, 2011 5:10 pm

Post by cjdrum »

Nope, I do. More hats :twisted:

Four men are brought to a beach by a crazed lunatic. He proceeds to dig four holes in the sand - three on one side of a wall, in a line parallel to it, and one on the other side. All men are facing the wall.
He then shows the men that he has five hats - three white, two black - and randomly places them on the men's heads so that they cannot see any hats except of the people in front of them. They can't see through the wall.
The lunatic says to the men, "If any one of you is able to tell me which colour hat you are wearing, you will all go free. However, if any of you says anything that isn't a correct guess, I will cut your heads off."

The men stay silent for a few moments, before the man at the front of the group of three says "My hat is white." How did he know?
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Post Post #614 (isolation #30) » Wed Jul 27, 2011 5:11 pm

Post by cjdrum »

EBWOP: The line of three is
perpendicular
to the wall. Not parallel.
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Post Post #616 (isolation #31) » Wed Jul 27, 2011 5:34 pm

Post by cjdrum »

The fifth hat is not placed on anyone's head, and no one can see it.
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Post Post #619 (isolation #32) » Wed Jul 27, 2011 6:14 pm

Post by cjdrum »

Espeonage got it.
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Post Post #756 (isolation #33) » Wed Aug 03, 2011 3:58 pm

Post by cjdrum »

Not necessarily anyone?

:P

(but I'll give it to SK)
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Post Post #759 (isolation #34) » Wed Aug 03, 2011 5:29 pm

Post by cjdrum »

Spoiler: Answer
House 1House 2House 3House 4House 5
ColourYellowBlueRedGreenWhite
NationalityNorwegianDaneBritGermanSwede
DrinksWaterTeaMilkCoffeeBeer
SmokesDunhillBlendsPall MallPrinceBlue Masters
PetCatsHorseBirdsDogs

So the German owns the fish.
But I'll let SK have it :D


As for the other one... They all have an odd number of digits. Maybe each pair is a set of coordinates? I'll look into it.
The
Australian Legendary Trio
is alive and kicking (American butt)!
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cjdrum
cjdrum
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cjdrum
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Location: Somewhere that isn't where you are... Thankfully.

Post Post #760 (isolation #35) » Wed Aug 03, 2011 5:34 pm

Post by cjdrum »

So I found a few neat little things:

- Firstly, there is one number that is in there twice.
diginova wrote:
A
.
nother S
.
mall C
.
ollection of I
.
mmense I
.
ntegers
(puzzle 2011.1.2.5)
3390066960
2716716990
142488921960
34441680
1051397257358448
2921407440
5460
2162928096
294043460256

344760
294043460256

38544100
13344757458552
49419000
5694
3369773440
32579316

- Secondly, the anagram.
A
nother
S
mall
C
ollection of
I
mmense
I
ntegers. I just don't know what exactly I have to do to get there, so...
The
Australian Legendary Trio
is alive and kicking (American butt)!

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