Math and Logic Puzzles

For completed/abandoned Mish Mash Games.
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Post Post #5 (isolation #0) » Sat Jul 09, 2011 6:32 am

Post by DonJosh »

StrangerCoug wrote:
Timmy, who is a gambling addict, enters a casino with $50 at 7:00 PM. He loses $20 in his first five minutes, but in the next five minutes he is able to make $15 of it back. He loses $20 more in his third five minutes, wins $15 back in his fourth five minutes, and so on in that cycle. At what time will he run out of money?


He ran out of money at 8:05.
At 8:00, he had $20. He lost it by 8:05. You can't regain money if you have none to start.
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Post Post #6 (isolation #1) » Sat Jul 09, 2011 6:33 am

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DAMMIT kcda ninja'd me :(
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Post Post #9 (isolation #2) » Sat Jul 09, 2011 8:22 am

Post by DonJosh »

Agh! Sorry for being so late. I was out. Anyhoo, lets start with a classic, just cuz I'm too tired to think...

You are traveling by foot to a shop in the City of Truth, where everybody tells the truth. You reach a fork in the road. You know the City of Truth is one way, but you don't know which. You also know that the City of Lies, where everybody lies, is on the opposite side of the road as the City of Truth. There are two children standing at the fork. You can tell that one of them is from the City of Truth, and one is from the City of Lies, but you cant tell them apart. You can ask them one question. What would be the best question to ask?

Sorry for unoriginality and possibly awkward wording, but I'm already late enough as is
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Post Post #14 (isolation #3) » Sat Jul 09, 2011 8:48 am

Post by DonJosh »

Espeonage got it
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Post Post #15 (isolation #4) » Sat Jul 09, 2011 8:48 am

Post by DonJosh »

And TS ninja'd me twice
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Post Post #17 (isolation #5) » Sat Jul 09, 2011 8:50 am

Post by DonJosh »

Tragedy wrote:
DonJosh wrote:Espeonage got it


In a logical way, TS' question would be more correct.


He only has one question. Now how does he know where the City of Truth is?
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Post Post #28 (isolation #6) » Sat Jul 09, 2011 9:05 am

Post by DonJosh »

Espeonage wrote:
animorpherv1 wrote:TS should win that. Espe asked a question to both, which is 2 questions. For TS's, all you need to do is ask one of them.


How did I ask a question to both?


1. He only asked one question to one person
2. TS is still lost at the fork.

Espeonage's question now
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Post Post #57 (isolation #7) » Sat Jul 09, 2011 11:55 am

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Twistedspoon wrote:what is the airspeed velocity of an unladen swallow?

African or European?
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Post Post #60 (isolation #8) » Sat Jul 09, 2011 12:00 pm

Post by DonJosh »

WHAT is your name?

Sir Gallahad of Camelot!
WHAT is your quest?

I seek the Holy Grail!
WHAT is your favourite colour?

Blue! ... No, Yel... *ahhh*
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Post Post #398 (isolation #9) » Tue Jul 19, 2011 1:23 pm

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I really don't feel like using the images and the table and everything...

Rows A-D
Columns 1-4

A1: AS
A2: JC
A3: KH
A4: QD
B1: QH
B2: KD
B3: JS
B4: AC
C1: JD
C2: AH
C3: QC
C4: KS
D1: KC
D2: QS
D3: AD
D4: JH
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Post Post #399 (isolation #10) » Tue Jul 19, 2011 1:51 pm

Post by DonJosh »

ImageImageImageImage
ImageImageImageImage
ImageImageImageImage
ImageImageImageImage
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Post Post #401 (isolation #11) » Tue Jul 19, 2011 1:53 pm

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I'll make a new puzlle tmrw
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Post Post #410 (isolation #12) » Wed Jul 20, 2011 12:18 pm

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Sudo_Nym can go, I can't find a challenging enough puzzle.
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Post Post #599 (isolation #13) » Wed Jul 27, 2011 2:28 pm

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10 prisoners.

Divide the bottles into 10 groups of 100

Prisoner A drinks combined drops from all bottles in Group A
Prisoner B drinks combined drops from all bottles in Group B
etc.
Prisoner J drinks combined drops from all bottles in Group J

Lets say Prisoner J dies.

Prisoner A drinks combined drops from 12 bottles in Group J
Prisoners B-I each drink combined drops from 11 bottles in Group J

Lets say Prisoner I dies.

Prisoners A-C drink combined drops from 2 bottles in Group J-I
Prisoners D-H drink a drop from one bottle each in Group J-I
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Post Post #604 (isolation #14) » Wed Jul 27, 2011 2:40 pm

Post by DonJosh »

Darned 24-hour time limit.
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Post Post #612 (isolation #15) » Wed Jul 27, 2011 5:02 pm

Post by DonJosh »

I have another Hat riddle if cj doesnt want to go.
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Post Post #615 (isolation #16) » Wed Jul 27, 2011 5:22 pm

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Wait... there are five hats, but only four dudes?
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Post Post #624 (isolation #17) » Thu Jul 28, 2011 3:54 am

Post by DonJosh »

Wrong. Its going to the left. If it were going to the right, you would be able to see the door.
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Post Post #627 (isolation #18) » Thu Jul 28, 2011 6:38 am

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Oh ya lol... I forgot about European driving laws XD

*Canadian, but whatever.

Should I go ahead with the next one?
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Post Post #628 (isolation #19) » Thu Jul 28, 2011 6:56 am

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Not accepting defeat, the hat-king sets up yet another challenge for his 100 wise men. He escorts them all into a dark room where half of the men are given red hats, while the other half are given blue hats. The room is pitch black, and no one can see anything. The king then tells them that he is standing next to a door. On the other side of that door is an illuminated room. The king challenges the men to enter the illuminated room one by one and form a line with all their hats alternating colour (Red, Blue, Red, Blue, Red, Blue, Red). However, once they are past the door, they may not return to the dark room, touch each other, or communicate in any way. The king gives the men time to devise a plan in the dark room. When eventually, much to his surprise, the men walk through the door one by one and form the line he challenged them to make. What was their plan?
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Post Post #630 (isolation #20) » Thu Jul 28, 2011 7:27 am

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There is no communication allowed when in the illuminated room. Also, they enter the room one by one.
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Post Post #632 (isolation #21) » Thu Jul 28, 2011 7:54 am

Post by DonJosh »

No.
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Post Post #635 (isolation #22) » Thu Jul 28, 2011 8:00 am

Post by DonJosh »

-.- Hm. I must've gotten the question wrong.
Since thats not the answer I'm looking for, lets assume it doesnt work, and reset the guess count to 0.
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Post Post #637 (isolation #23) » Thu Jul 28, 2011 8:15 am

Post by DonJosh »

^ correct
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Post Post #706 (isolation #24) » Fri Jul 29, 2011 11:33 am

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Damn I was gonna say coffin :(
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Post Post #712 (isolation #25) » Fri Jul 29, 2011 11:50 am

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Open the door, put him in?
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Post Post #717 (isolation #26) » Fri Jul 29, 2011 12:59 pm

Post by DonJosh »

I've got one.

By adding on straight line to this equation, make it true:

4+4+4=448
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Post Post #719 (isolation #27) » Fri Jul 29, 2011 1:04 pm

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^yup
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Post Post #721 (isolation #28) » Fri Jul 29, 2011 1:12 pm

Post by DonJosh »

4.366062299143245 m

Pythagorean theorum

√(42+1.752)
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Post Post #722 (isolation #29) » Fri Jul 29, 2011 1:13 pm

Post by DonJosh »

Damn. Well, thats the answer with the 2x2x5 room
DAMN NINJAS
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Post Post #1176 (isolation #30) » Sat Nov 26, 2011 5:59 pm

Post by DonJosh »

2
12
1112
3112
132112
1113122112
311311222112
13211321322112
1113122113121113222112

Divide each number into separate digits. If the same digit occurs twice in a row, group them together. The state how many of each digit there are.
(eg
1113122112
111 3 1 22 11 2
"There are three ones, one three, one one, two twos, two ones, and one two."
311311222112)
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Post Post #1180 (isolation #31) » Sun Nov 27, 2011 2:37 am

Post by DonJosh »

You never will. The only way to do that is to split a group. Puzzle coming in a bit...
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