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Posted: Tue Sep 01, 2020 10:48 am
by Ircher
Ircher decided that the universe could use a number. He applied the secret power of base conversion to form the next number.

17
(in decimal) converted to octal =
21

Posted: Tue Sep 01, 2020 11:23 am
by StrangerCoug
After Jake ate the keleven, Coug realized that he was hungry, too, so he got a little carried away and made a square pi.


pi
^
2
=
pi^2

In post 49, Jake The Wolfie wrote:(Coug, if you want, you can edit your prev. message to add 11, or ask me how you want it made.)
(Done.)

Posted: Tue Sep 01, 2020 12:49 pm
by Jake The Wolfie
100
/
5
=
20

Posted: Tue Sep 01, 2020 1:36 pm
by StrangerCoug
Among the Greek letters that existed, there were pi and tau. Now there would be zeta(2), though that being a function with a number Coug had already created as a sole argument, he couldn't directly use the function. However, he knew what the function would output:


pi^2
/
6
=
pi^2/6

Posted: Tue Sep 01, 2020 1:42 pm
by Ircher
Fun Fact: You can construct any square root of a rational length using just a compass and a straightedge. Speaking of square roots...


sqrt(
15
) =
sqrt(15)

Posted: Tue Sep 01, 2020 1:53 pm
by Jake The Wolfie
So would this require 4 compasses and 4 straightedges?

sqrt(
sqrt(15)
) =
sqrt(sqrt(15))

Posted: Tue Sep 01, 2020 2:04 pm
by Ircher
No, it would only require one compass and one straightedge. You would just have to do the process twice.

sqrt(
sqrt(sqrt(15))
=
sqrt(sqrt(sqrt(15)))


(Because why not?)

Posted: Tue Sep 01, 2020 2:13 pm
by Jake The Wolfie
sqrt(sqrt(sqrt(15)))
^
3
=
(sqrt(sqrt(sqrt(15))))^3


:)

Posted: Tue Sep 01, 2020 3:38 pm
by StrangerCoug
"Square roots of square roots?" Coug asked. He saw that, by simplification, the square root of the square root was the fourth root, and the square root of the square root of the square root was the eighth root. But why did the root have to be a power of two? Odd roots had the power that taking one of a negative real number gave another negative real number.


cbrt(
-3
) =
-cbrt(3)

Posted: Wed Sep 02, 2020 3:42 am
by D3f3nd3r
With ten and e already here as the two most common bases for logarithms, D3f set out to use the third most common base for a logarithm instead.


lg(
10
) =
lg(10)
(log base-2)

Somewhere in the distance, a computer scientist cried out in joy.

Posted: Wed Sep 02, 2020 5:47 am
by StrangerCoug
(That's actually the common log of 10. A valid number, but not the base of the binary log xD)

Complex conjugate of (
255.75+i
) =
255.75-i

Posted: Wed Sep 02, 2020 5:59 am
by Jake The Wolfie
255.75-i
+
i
=
255.75

Posted: Wed Sep 02, 2020 6:34 am
by D3f3nd3r
"Lg" is the common log?

Idk I'm an engineer, so "log" is common and "ln" is natural

255.75-i
-
i
=
255.75-2i

Posted: Wed Sep 02, 2020 8:57 am
by Jake The Wolfie
(
255.75-2i
)^
2
=
65404.0625-1023i

Posted: Wed Sep 02, 2020 2:04 pm
by StrangerCoug
In post 62, D3f3nd3r wrote:"Lg" is the common log?

Idk I'm an engineer, so "log" is common and "ln" is natural
(Just plain "log" is ambiguous and depends on the context you're talking about. That's why the symbol lg (without the o) was devised.)

Im(
65404.0625-1023i
) =
1023

Posted: Wed Sep 02, 2020 2:08 pm
by Ircher
For computer scientists, log always indicates the base-2 log. That allows us to say things like binary search is O(log(N)). So yeah, log depends on context and who you are talking to.

1023
+
1
=
1024

Posted: Wed Sep 02, 2020 2:11 pm
by Jake The Wolfie
1024
x
i
=
1024i

Posted: Wed Sep 02, 2020 9:22 pm
by Sirius9121
From the darkness, a pokemon, Growlithe, is born

Posted: Wed Sep 02, 2020 9:24 pm
by Sirius9121
Ah, e and pi. Hmm

pi
+
e
=
pi+e (5.85987448205)

'True pie', said the Growlithe

Posted: Thu Sep 03, 2020 6:15 am
by Jake The Wolfie
1024
+
1024i
=
1024+1024i

Posted: Thu Sep 03, 2020 6:21 am
by StrangerCoug
Modulus of
1024+1024i
=
1024*sqrt(2)

Posted: Thu Sep 03, 2020 12:34 pm
by Sirius9121
1024*sqrt(2)
^
2
=
2097152

Posted: Thu Sep 03, 2020 3:08 pm
by StrangerCoug
(You technically need the parentheses around my entire number before squaring it or it'll be 2048, but I get you.)

log_
2
(
2097152
) =
21

Posted: Thu Sep 03, 2020 4:52 pm
by Sirius9121
128
+
2
=
130


(i need this)

Posted: Mon Sep 07, 2020 12:33 pm
by StrangerCoug
Who would have known that an imaginary number to the power of an imaginary number would be a real number?


i
^
i
=
e^(-pi/2)