CFJ's The One I Cannot Kill [Game Ended]

[or]

Setup information

This is an Open game (The One I Cannot Kill), with the following role list:

1 Mafia Semi-Priest
2 Vanilla Townies

The Mafia Semi-Priest is in most respects a Mafia Goon. However, there is one specific town-aligned player that they cannot hammer (i.e. cannot cast the deciding vote against); if they attempt to do this, they will be modkilled. (They are allowed to hammer the other town-aligned player, and are allowed to vote for either player if doing so would not hammer them.)

Game ended. Town of Ircher and TemporalLich won.

Player List:

Ircher
Elements
TemporalLich

[Ircher]

/in
Let's get rollin'!

[Elements]

/in

[Elements]

I saw this setup a few days ago and thought it looked fun

[TemporalLich]

idek anymore

/in

hammer

[or]

Hammered. Rolling dies and sending PMs

[Elements]

12

[Elements]

that is a number

[TemporalLich]

NaN

[Ircher]

3 | 12 because 12 = 3(4).

[TemporalLich]

2 to the power of 4 is 16

[Elements]

NaN

Should be Na3N

[or]

Day has begun.

Vote count 0:

Ircher:
Elements:
TemporalLich :

Takes 2 to lynch.

[Elements]

When will time end?
And don't say at the end of time

[or]

Day ends in 35 minutes just in time for TL's game

[TemporalLich]

RVS + LYLO = random math facts

[Ircher]

Let's play a game.

We start with a number, let's say 100. On your turn, you must choose an integer >= 2 that is a factor of the previous number excluding that number. The first unable to do so loses.

(E.g: If we start with 20, you could do 4 on turn one as 4 | 20. Then on my turn, I can select 2 as 2 | 4. You then lose because no integer greater than two divides two.)

I'll challenge Elements first. Whoever loses plays TemporalLich. Whoever loses that one gets voted.

[Elements]

Vampire numbers are even number of digit numbers that have to factors with half the number of digits which contain the same numbers as the original number eg: 1260 = 12 * 60

[Elements]

Let's play a game.

We start with a number, let's say 100. On your turn, you must choose an integer >= 2 that is a factor of the previous number excluding that number. The first unable to do so loses.

(E.g: If we start with 20, you could do 4 on turn one as 4 | 20. Then on my turn, I can select 2 as 2 | 4. You then lose because no integer greater than two divides two.)

I'll challenge Elements first. Whoever loses plays TemporalLich. Whoever loses that one gets voted.

who starts?

[Ircher]

you
Choose a number that divides 100.

[Elements]

2

[Ircher]

loser goes first in the next game.

[Elements]

i think i've broken the game?

[Ircher]

Zzz I should adjust the rules.... Guess that means Temporal gets voted though

[TemporalLich]

yeah I could see the breaking strategy from a mile away... I would have said "5" though