Sequencer | StrangerCoug's turn

[skitter30]

hi i'm replacing jackal

i play 324, 18, 17 as numbers where each successive digit is strictly greater than the previous one

[skitter30]

sorry that was some kind of brainfart

324, 18, 33, 99, 60 as numbers divisible by 3

[skitter30]

ok third time's the charm:

324, 18, 99 as numbers with a factor that is a square number
i.e. 18 and 99 have 9 as a factor
324 has 9 and 324 as factors

[skitter30]

17, 33, 73 as numbers that are congruent to 1 mod 8

[skitter30]

@plot i think you completed the wrong sequence for micc; he completed 'numbers with a factor that is a square', not 'square numbers'

i play 1, 10, 23 as numbers that when converted to number of days in the year would be in the month of january

(i.e. 1 is jan 1st; 10 is jan 10th; 32 would be february 1st, 33 would be february 2nd, and so on)

[skitter30]

That is true

[skitter30]

ok
60 to numbers that end in 0

[skitter30]

10, 23, 36, 49 as numbers congruent to 10 mod 13

[skitter30]

[10, 23, 36, 59] { n ≡ 10 (mod 13) } numbers congruent to 10 mod 13

the 59 ought to be a 49

[skitter30]

add 196 to numbers that end in 6

[skitter30]

ahhhhhhh sorry

add 1 to numbers that are congruent to 1 mod 8

[skitter30]

[30, 58, 87] 2 digit numbers where one digit is prime and the other is not

add 31 and 47 to this

[skitter30]

[4, 21, 30] { n = a010d + a110d-1 + ... + ad100 with Σi∈[0,d]ai | 12 } sum of the digits is a factor of 12

2, 84, 1, 3

[skitter30]

i kinda assumed he was trolling

but we'd seriously count synesthesia?
cuz i'm synesthetic and then i could say all green numbers (which for me would be anything that starts with a 3, and sometimes numbers that end in a 3)

i think that would be a little silly tho because you lot would have no way of verifying what i'm seeing

[skitter30]

ah misunderstood what you were saying, fair enough!

[skitter30]

[14, 62, 256] { (2 | n) ∧ (3 | n ↓ 5 | n) } divisible by 2 but not by 3 or 5

2, 4, 8, 56

[skitter30]

[19, 46, 64, 361] { n = a010d + a110d-1 + ... + ad100 with Σi∈[0,d]ai = 10; ai ≥ 0, d > 0; k ∈ ℤ } numbers whose digit sum equals 10

add 82

[skitter30]

[1, 125, 216] at least one digit is 1

144

[skitter30]

1, 19, 67] { n ≡ 1 (mod 6) } congruent to 1 mod 6

13

[skitter30]

Pass

[skitter30]

Hey i'll in again if there are more slots.
I'm going to be vla wednesday and thursday tho

[skitter30]

166, 337, 333

as numbers with at least one immediately repeating digit

[skitter30]

17 and 137 to primes

[skitter30]

189, 234, 342

As numbers that are either square or are rearranged digits of a square number
(I.e. 342 is 324 rearranged)

[skitter30]

Sorry not 189, just the other 2

[skitter30]

3 digit numbers where the last digit is less than the sum of the first two digits

342, 356, 234

[skitter30]

90, 322, 303, 329

Numbers wherein if you remove the smallest digit, you're left with a composite number

[skitter30]

[39, 86, 261] can be spelled digit by digit with ten or fewer letters in English, no leading zeroes, 0 is spelled as zero

32 - three two (8)
33 - three three (10)
76 - seven six (8)
93 - nine three (7)

[skitter30]

235, 268, 242

numbers with a two-digit prime factor
235 (47 * 5)
268 (67 * 4)
242 (11 * 11 * 2)

[skitter30]

multiple of 27

81, 189, 216, 324

[skitter30]

actually i don't have 216, scratch that, but keep the others

[skitter30]

I think 72 hours would be better for auto-moving during V/LAs because I know skitter has a weekly V/LA for the Sabbath. I wouldn't want a V/LA rule to affect her disproportionately. I have a similar rule of giving people extra (but not unlimited) time while V/LA in my mafia games that works fairly well.

thanks, i appreciate it

[skitter30]

numbers wherein if i spell the numbers out digit by digit in english, i can take the first letter of each digit and use those letters to form an english word (i.e. anagrams are allowed)

ex: 196 -> one nine six -> ons -> son is a valid english word
ex: 319 -> three one nine -> ton
ex: 128 -> one two eight -> ote -> toe

playing these three numbers ^

also

i will be vla until sunday without internet access

[skitter30]

Complete skitter's sequence:

193 > ont > ton
172 > ost > sot
158 > ofe > foe
288 > tee

Yeah i figured it woupd be easy to complete but it was a fun one

[skitter30]

[95, 138, 246] squarefree composite numbers

58, 335, 314, 247

[skitter30]

328, 28, 276, 275

as numbers that contain either {28} or {27}

[skitter30]

[134, 146, 238, 248] { n = 100*a + 10*b + c with 0 < a < b < c < 10} 3 digit numbers whose digits are in strictly ascending order

145, 139, 236

[skitter30]

[361, 283, 343, 223] { n ≡ 1 (mod 6) } (multiples of 6) + 1

whoops sorry !!!

241, 355, 331, 91

[skitter30]

47, 74, 131, 245

remove each digit that is a power of 2 and you're left with a prime
(for the purposes of this sequence, 1 = 2 ^0 would count as a power of 2)

[skitter30]

add 160 to multiples of 5

[skitter30]

i don't either

[skitter30]

numbers that are multiples of 3
102, 366, 87

[skitter30]

[81, 189, 324, 27] { 27 | n } multiples of 27

297

[skitter30]

49, 94, 148
numbers whose digits sum to 13

[skitter30]

[23, 293, 161] { n ≡ 5 (mod 6) } numbers equivalent to 5 mod 6

147

[skitter30]

[69, 99, 269, 294] numbers that contain a 9

96

[skitter30]

pass

[skitter30]

pass

[skitter30]

pass

[skitter30]

Pass.

Whoo good job lilith !

[skitter30]

What was the deck for the game before this one

[skitter30]

i didn't get any cards with a 2 in it in for the last several rounds so a lot of the sequences were nonviable for me :/