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Ircher
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Post Post #50  (ISO)  » Tue Sep 01, 2020 4:48 pm

Ircher decided that the universe could use a number. He applied the secret power of base conversion to form the next number.

17 (in decimal) converted to octal = 21
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StrangerCoug
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Post Post #51  (ISO)  » Tue Sep 01, 2020 5:23 pm

After Jake ate the keleven, Coug realized that he was hungry, too, so he got a little carried away and made a square pi.

pi^2 = pi^2

In post 49, Jake The Wolfie wrote:(Coug, if you want, you can edit your prev. message to add 11, or ask me how you want it made.)

(Done.)
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Jake The Wolfie
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Post Post #52  (ISO)  » Tue Sep 01, 2020 6:49 pm

100/5=20

StrangerCoug
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Post Post #53  (ISO)  » Tue Sep 01, 2020 7:36 pm

Among the Greek letters that existed, there were pi and tau. Now there would be zeta(2), though that being a function with a number Coug had already created as a sole argument, he couldn't directly use the function. However, he knew what the function would output:

pi^2/6 = pi^2/6
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Ircher
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Post Post #54  (ISO)  » Tue Sep 01, 2020 7:42 pm

Fun Fact: You can construct any square root of a rational length using just a compass and a straightedge. Speaking of square roots...

sqrt(15) = sqrt(15)
Last edited by Ircher on Tue Sep 01, 2020 7:57 pm, edited 1 time in total.
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Post Post #55  (ISO)  » Tue Sep 01, 2020 7:53 pm

So would this require 4 compasses and 4 straightedges?

sqrt(sqrt(15)) = sqrt(sqrt(15))

Ircher
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Post Post #56  (ISO)  » Tue Sep 01, 2020 8:04 pm

No, it would only require one compass and one straightedge. You would just have to do the process twice.

sqrt(sqrt(sqrt(15)) = sqrt(sqrt(sqrt(15)))

(Because why not?)
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Post Post #57  (ISO)  » Tue Sep 01, 2020 8:13 pm

sqrt(sqrt(sqrt(15)))^3 = (sqrt(sqrt(sqrt(15))))^3

:)

StrangerCoug
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Post Post #58  (ISO)  » Tue Sep 01, 2020 9:38 pm

"Square roots of square roots?" Coug asked. He saw that, by simplification, the square root of the square root was the fourth root, and the square root of the square root of the square root was the eighth root. But why did the root have to be a power of two? Odd roots had the power that taking one of a negative real number gave another negative real number.

cbrt(-3) = -cbrt(3)
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D3f3nd3r
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Post Post #59  (ISO)  » Wed Sep 02, 2020 9:42 am

With ten and e already here as the two most common bases for logarithms, D3f set out to use the third most common base for a logarithm instead.

lg(10) = lg(10) (log base-2)

Somewhere in the distance, a computer scientist cried out in joy.
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StrangerCoug
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Post Post #60  (ISO)  » Wed Sep 02, 2020 11:47 am

(That's actually the common log of 10. A valid number, but not the base of the binary log xD)

Complex conjugate of (255.75+i) = 255.75-i
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Jake The Wolfie
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Post Post #61  (ISO)  » Wed Sep 02, 2020 11:59 am

255.75-i + i = 255.75

D3f3nd3r
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Post Post #62  (ISO)  » Wed Sep 02, 2020 12:34 pm

"Lg" is the common log?

Idk I'm an engineer, so "log" is common and "ln" is natural

255.75-i - i = 255.75-2i
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Jake The Wolfie
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Post Post #63  (ISO)  » Wed Sep 02, 2020 2:57 pm

(255.75-2i)^2 = 65404.0625-1023i

StrangerCoug
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Post Post #64  (ISO)  » Wed Sep 02, 2020 8:04 pm

In post 62, D3f3nd3r wrote:"Lg" is the common log?

Idk I'm an engineer, so "log" is common and "ln" is natural

(Just plain "log" is ambiguous and depends on the context you're talking about. That's why the symbol lg (without the o) was devised.)

Im(65404.0625-1023i) = 1023
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Ircher
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Post Post #65  (ISO)  » Wed Sep 02, 2020 8:08 pm

For computer scientists, log always indicates the base-2 log. That allows us to say things like binary search is O(log(N)). So yeah, log depends on context and who you are talking to.

1023 + 1 = 1024
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Post Post #66  (ISO)  » Wed Sep 02, 2020 8:11 pm

1024 x i = 1024i

Sirius9121
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Post Post #67  (ISO)  » Thu Sep 03, 2020 3:22 am

From the darkness, a pokemon, Growlithe, is born
Last edited by Sirius9121 on Thu Sep 03, 2020 3:27 am, edited 1 time in total.
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Thus creating the Astley Paradox.
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Post Post #68  (ISO)  » Thu Sep 03, 2020 3:24 am

Ah, e and pi. Hmm
pi+e=pi+e (5.85987448205)
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If you ask Rick Astley for his copy of the movie 'Up', he can not give it to you as he will never give you up.
However, by refusing to do so, he lets you down.
Thus creating the Astley Paradox.
*glares at Sirius*Well played my friend, well played. - Aristophanes

Jake The Wolfie
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Post Post #69  (ISO)  » Thu Sep 03, 2020 12:15 pm

1024 + 1024i = 1024+1024i

StrangerCoug
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Post Post #70  (ISO)  » Thu Sep 03, 2020 12:21 pm

Modulus of 1024+1024i = 1024*sqrt(2)
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Sirius9121
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Post Post #71  (ISO)  » Thu Sep 03, 2020 6:34 pm

1024*sqrt(2)^2=2097152
If you ask Rick Astley for his copy of the movie 'Up', he can not give it to you as he will never give you up.
However, by refusing to do so, he lets you down.
Thus creating the Astley Paradox.
*glares at Sirius*Well played my friend, well played. - Aristophanes

StrangerCoug
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Post Post #72  (ISO)  » Thu Sep 03, 2020 9:08 pm

(You technically need the parentheses around my entire number before squaring it or it'll be 2048, but I get you.)

log_2(2097152) = 21
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Sirius9121
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Post Post #73  (ISO)  » Thu Sep 03, 2020 10:52 pm

128+2=130

(i need this)
If you ask Rick Astley for his copy of the movie 'Up', he can not give it to you as he will never give you up.
However, by refusing to do so, he lets you down.
Thus creating the Astley Paradox.
*glares at Sirius*Well played my friend, well played. - Aristophanes

StrangerCoug
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Post Post #74  (ISO)  » Mon Sep 07, 2020 6:33 pm

Who would have known that an imaginary number to the power of an imaginary number would be a real number?

i^i = e^(-pi/2)
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