The Number Game

For completed/abandoned Mish Mash Games.
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Post Post #5 (isolation #0) » Fri Sep 23, 2016 8:17 am

Post by Something_Smart »

4^3+9+4=77
oh lol I did that before I realized you can do multidigits :P
without them is more hardcore, but not always possible...
Original Roll String: 4d10
4 10-Sided Dice: (10, 9, 8, 4) = 31

Original Roll String: 1d91+9
1 91-Sided Dice: (75)+9 = 84
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Post Post #7 (isolation #1) » Fri Sep 23, 2016 8:32 am

Post by Something_Smart »

wait what
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Post Post #9 (isolation #2) » Fri Sep 23, 2016 8:34 am

Post by Something_Smart »

thank you lol :P

I'll solve it, I promise
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Post Post #10 (isolation #3) » Fri Sep 23, 2016 8:37 am

Post by Something_Smart »

9*(sqrt(3)^4)-4=77

just use my original numbers
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Post Post #12 (isolation #4) » Fri Sep 23, 2016 8:40 am

Post by Something_Smart »

uh what do we do with the 10?
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Post Post #14 (isolation #5) » Fri Sep 23, 2016 8:41 am

Post by Something_Smart »

so the zero is literally useless :/
also lol @ the square root of .5th root
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Post Post #15 (isolation #6) » Fri Sep 23, 2016 9:04 am

Post by Something_Smart »

0+5^sqrt(sqrt(sqrt(2^8)))=25
that was harder than it had any right to be

Original Roll String: 4d10
4 10-Sided Dice: (6, 9, 4, 7) = 26
Original Roll String: 1d91+9
1 91-Sided Dice: (69)+9 = 78
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Post Post #17 (isolation #7) » Fri Sep 23, 2016 10:21 am

Post by Something_Smart »

:facepalm:
(4+7)*8+3=91
Original Roll String: 4d10
4 10-Sided Dice: (3, 5, 1, 5) = 14
Original Roll String: 1d91+9
1 91-Sided Dice: (20)+9 = 29
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Post Post #20 (isolation #8) » Fri Sep 23, 2016 3:53 pm

Post by Something_Smart »

hehehehe
(3*4+.9999...)*6=78
Original Roll String: 4d10
4 10-Sided Dice: (8, 7, 3, 10) = 28
Original Roll String: 1d91+9
1 91-Sided Dice: (52)+9 = 61
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Post Post #24 (isolation #9) » Fri Sep 23, 2016 7:06 pm

Post by Something_Smart »

no, and I tried some pretty desperate stuff :/
I definitely agree with removing 0. Most of the time it's just a waste.

how did you play with decimal points to get 90.6?
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Post Post #28 (isolation #10) » Sat Sep 24, 2016 12:46 pm

Post by Something_Smart »

you can get arbitrarily close to 66 by taking repeated square roots of 5 and 7 (or of 12 if you prefer)...

but man, trying to get exactly 66 is difficult if not impossible :/

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