marathon with friends

[Elements]

But I'm town Ausuka! I'm town!

Unless you can provide at least 3 mathematical proofs I don't believe you.

not this again

[Elements]

VOTE: elements

[northsidegal]

explain your reads, chennis?

[Elements]

shrug

will work on my quick time communication skills then

I would've gone with "You playing icher?"

[northsidegal]

i honestly don't have any townreads yet.

[chennisden]

elements is town and im not so solid on ausuka but idk

it doesnt feek agenday

[or]

vc 2

ircher
ausuka
elements - ausuka, elements
chennis
nsg -

3 to monty

[Ircher]

But I'm town Ausuka! I'm town!

Unless you can provide at least 3 mathematical proofs I don't believe you.

I could do three really easy ones.

Proposition 1: The sum of two even integers is even.

Proof: Let a and b be arbitrary integers. Then by definition of even, a = 2k and b = 2l where k and l are integers. Thus, a + b = 2k + 2l = 2(k + l). The sums of integers are integers, so the resulting number is an even integer. QED.

Should I continue?

[Elements]

3 to monty

I like that wording

[chennisden]

VOTE: nsg

[northsidegal]

i think ircher and ausuka probably lean scum over everyone else but it's not that strong

[Elements]

But I'm town Ausuka! I'm town!

Unless you can provide at least 3 mathematical proofs I don't believe you.

I could do three really easy ones.

Proposition 1: The sum of two even integers is even.

Proof: Let a and b be arbitrary integers. Then by definition of even, a = 2k and b = 2l where k and l are integers. Thus, a + b = 2k + 2l = 2(k + l). The sums of integers are integers, so the resulting number is an even integer. QED.

Should I continue?

Ew, don't be pretentious with your QED's. Use the square instead, much nicer.

[Ausuka]

But I'm town Ausuka! I'm town!

Unless you can provide at least 3 mathematical proofs I don't believe you.

I could do three really easy ones.

Proposition 1: The sum of two even integers is even.

Proof: Let a and b be arbitrary integers. Then by definition of even, a = 2k and b = 2l where k and l are integers. Thus, a + b = 2k + 2l = 2(k + l). The sums of integers are integers, so the resulting number is an even integer. QED.

Should I continue?

I meant mathematical proof of you being town but i guess this works too

[Ircher]

I'm on mobile and the box requires a special character. QED does not.

[Elements]

icher nsg scum team. game solved

[northsidegal]

icher nsg scum team. game solved

how's that?

[Elements]

neither of you will be confirmed town when we monty

[Ircher]

Proposition 2: I am town.

Proof: Suppose not. Suppose I am scum. Then by definition, I must have a scum partner. But I do not have a scum partner--a contradiction! Thus, I am town. []

[northsidegal]

?

[Ausuka]

Proposition 2: I am town.

Proof: Suppose not. Suppose I am scum. Then by definition, I must have a scum partner. But I do not have a scum partner--a contradiction! Thus, I am town. []

Part of me wants to locktown you but the other part of me wants to actually play to some extent and not be annoying and that part is winning out

[Elements]

[]

nicely done. I approve.
I retract my proposed scum team.

[Ausuka]

nsg/chennis let's go

[Ircher]

VOTE: Ausuka

[Ircher]

we should select ausuka; they seem town.

[Ausuka]

i don't understand why voting elements isn't the play here