In post 2231, mastina wrote:RE:
2228, it might seem a bit unfair, but to those who were Not Voting, they get counted as BOTH voting-Zelda and voting-Zoe for the purposes of the division.
Is-Zelda = A
Is-Zoe = B
Guessed-Zelda = C
Guessed-Zoe = D
Voted-Zoe = E
Voted-Zelda = F
TRIPLE COMBO STACK(s):
ACE: ActionDan, Vecna?, randomidget, chesskid3, Llamarble (+EddieFenix)
BDF: Dunkerdoodles
---
ACF: Desperado (+EddieFenix, ??Vecna??)
ADE: Screenplay
ADF: None that I can see. (So, nobody is a Zelda who guessed Zoe and voted Zelda.)
BCE: (+SnarkySnowman)
BCF: Chickadee, drealmerz7 (+SnarkySnowman)
BDE: MarioManiac4
Did I do my calculations correctly here?
Because I just gotta say. Regardless of scum distribution that ACE pile looks suspicious.
We know that it can't be an exact scumteam mirror since the only inverse-ACE is Dunkerdoodles.
A_Es are ActionDan/Vecna/randomidget/chesskid/Llamarble
B_Fs are Dunkerdoodles/Chickadee/drealmerz/SnarkySnowman.
If the scumteam split in two, this is the most likely way they did so.
AC_s are ActionDan/Vecna/randomidget/chesskid/Llamarble/Desperado/EddieFenix
BD_s are Dunkerdoodles/MarioManiac4. This even split isn't impossible, but is less likely. Were there a split featuring these two, it'd likely be part of a larger multi-split.
_CEs are ActionDan/Vecna/randomidget/chesskid/Llamarble/EddieFenix/SnarkySnowman
_DFs are Dunkerdoodles. This can't be an even split; if this is a split, then it is part of a larger multi-split.
I don't quite have the head to calculate multi-splits. (In which the scumteam actively chose to distribute themselves differently at different points: voting a certain way for Being, voting a certain different way for Guessing, and voting a third way for the votecount today.)
But this covers most of the basics. Scumteam this game is going to be 4-8 players, probably 4-6 more realistically. If the scumteam has four/six members and went for common distributions, then they can have:
-All eggs in ACE basket
-Even split in A_E/B_Fs
-Even split in AC_s/BD_s (requires 4-man scumteam AND both Dunkerdoodles/MarioManiac4 as scum; unlikely)
-One ACE, one BCF, one ACF, remainder distributed in BDF/ADE/BCE/BDE
-Two ACE, two BCF (+remainder distributed in ACF/ADE/BDE)
...Maybe others, but I can't think of all the common distributions.
This only covers the common distributions though. It's fully possible to do a random-distribution, i.e., the scum either didn't coordinate, coordinated only partially on this and not on all three steps, didn't have all scum follow the plan (hey it happens), or simply coordinated in such a way that there was no obvious pattern to be found.
Did I mention this post is currently useless? Because yeah it's pretty worthless right now but I have faith that this information can later down the line crack the scumteam wide open. We just need to get there first.