[CHALLENGE] May Challenge

[Isis]

The third to last bullet should say "Day 1, the bot will alway hammer unless the L-1 vote is upon itself", I know that's what you meant but technically as written the bot votes a certain way initially and then is willing to move its vote to feed its lust for lolhammers.

[BBmolla]

fixed thank you

[T-Bone]

That's actually really cool I think.

If the bot is lynched and is Town, the Bot will immediately shoot both the players who voted it first and second.

That part confuses me though.

[Isis]

The bot shoots everyone but the hammerer if mislynched

[gobbledygook]

The Most Toxic Game on the Internet

9 players
2 vs 7

Mafia and town roles are randomized from this list.
Every player has a poison counter. If they reach poison stacks equal to their poison counter, they will die.
Mafia have 1 nightkill. With a priority of 8.
Mafia are informed of which roles are not included in the game as safeclaims.

3

Mafia

Singed

, Self Redirector, poison counter of 4, passively adds a poison stack to people who visit him, can target someone to redirect their ability to him, priority 5

Dr. Mundo

, Mafia Suicide Bomber, poison counter of 5

Twitch

, Mafia Poisoner (adds one to poison stack to a person), poisoner counter of 3, priority 4

9

Town

Soraka

, Healer, poison counter of 3 removes a poison stack from a player, priority 6

Sivir

, Spell Shield, poison counter of 3, the first ability to target Sivir will not succeed, priority 1

Cho'Gath

, posion counter of 4

Pyke

, Executioner (if someone has L-1 poison stacks and Pyke targets them, they will die), poison counter of 3, priority 3

Yuumi

, poison counter of 2

Teemo

, Trapper (puts a trap on a person that detonates if someone visits that player poisoning the player and all visitors), poison counter of 3, priority 2

Cassiopeia

, Poisoner (adds one to poison stack to a person), poison counter of 3, priority 7

Vladimir

, poison counter of 5

Fizz

, poison counter of 3

[Hectic]

Deepwolf Conspiracy

The game is either a Conspiracy [2 goons vs 7 town] or Innocent [9 town].

Town

: You can use your vote to lynch, and play the game normally. You can choose to leave at any point; mod registers game leaves at the end of every two IRL days.

If the game is Innocent, you win upon being lynched, or exiting the game. You lose if you're the last 5 Town.

If the game is Conspiracy, you win if both scum are lynched, and lose if a) you exit the game, or b) scum reach parity.

Mafia

: Achieve parity to win.

Nightless flipless. Or maybe I can make this flipful (eeks) and add a White Flag?

Hoctac, you may be interested in this inversion of Conspiracy!

This looks really cool lol. Don't flips hurt scum though? Why would you need to add a White Flag?

[Isis]

Re:toxic, because the mafia's mean poison counter is higher than town's, it's antitown for Cassiopeia to poison people in the dark. This problem applies to the other halfvigs too.

[gobbledygook]

Re:toxic, because the mafia's mean poison counter is higher than town's, it's antitown for Cassiopeia to poison people in the dark. This problem applies to the other halfvigs too.

That is by design.

[gobbledygook]

I wanted to explore arsonist-like setups.

[BBmolla]

That's actually really cool I think.

If the bot is lynched and is Town, the Bot will immediately shoot both the players who voted it first and second.

That part confuses me though.

Normally the game would go to LYLO with the Bot as the clear, but that doesn't work cause the human players are just gonna vote each other so it's up to the bot to decide.

So in that case, instead of getting a 1-shot Dayvig they get a 2-shot Dayvig with both shots used immediately on the first two players on the bot's lynch wagon.

[gobbledygook]

How does it actually work?

[BBmolla]

How does it actually work?

If this at me about my last post

Let's say the bot is lynched and town, the votes happened in the following order

Bot - 3 - Michael, Jim, Pam

The Bot immediately vengekills Michael and Jim, being the first two votes on the wagon, and the game ends. If Michael and Jim are both scum (which is... unlikely given all this), scum both die and town wins. If one of Michael and Jim is town, they both die and scum win.

[gobbledygook]

But like, how do you actually incorporate the bot? That’s where I’m confused.

[gobbledygook]

Is it just an option to vote for?

[T-Bone]

Why would you then lynch the bot if it just kills the two on the wagon?

[Isis]

Because the bot is scum? Generally there isn't onus on a mislynch to be good play for a townie.

The only question is "why would scum vote the bot first and second" and it would be a WIFOM thing for them to do so.

[callforjudgement]

If you're town and see two votes that aren't yours on the bot, you hammer. Either the bot is town, in which case you automatically win, or the bot is scum, in which case you just lynched scum.

This implies that scum who understand theory won't gang up on the bot, not even for WIFOM reasons.

[mith]

(need another replacement in that Fogies open game, if anyone here is interested)

[BBmolla]

But like, how do you actually incorporate the bot? That’s where I’m confused.

It literally just sits there

It's basically a slot you have to PoE by reading the other two

[Auro]

Town can force a 66% win in Triad Conspiracy

[Hectic]

Town can force a 66% win in Triad Conspiracy

Yeah, you can do some provable randomness using the hoods too. The hope is that people will agree that's boring and will just play normally.

[Isis]

Can you explain the 66% win that I suspect is a 67% win

[NotAJumbleOfNumbers]

Town can force a 66% win in Triad Conspiracy

Yeah, you can do some provable randomness using the hoods too. The hope is that people will agree that's boring and will just play normally.

why not just give town one shot only

[Auro]

Can you explain the 66% win that I suspect is a 67% win

When I say 66% I mean

exactly

66% Pops

Each hood individually picks a number. After all three hoods select a number, they out them. It's summed up, let the sum be X. Hoods are numbered 0,1,2.

Calculate X%3 and X%1100. (Remainders with 3 and 1100)

If X%1100<32, this is the strategy followed:
Each person picks a random number between 1 and 1000 secretly, and decides to vote themselves after that number of days.

If X%1100≥32, then the hood whose number is not X%3 doesn't vote itself, while the other two do.

The EV of this strategy is:
(1069/1100)*(2/3) + (32/1100)*[7/16] = 66%


(If town wants the 66.67% forced EV, they can chuck the X%100 part and simply have the non X%3 hoods vote themselves)

Your suspicions are wrong Pops

[northsidegal]

having only seen auro's post and not knowing what setup it's referring to i literally cannot imagine the kind of setup where that would be any strategy at all, much less one that apparently gives a forced win exactly 66% of the time